Math Paper

Chapter 6 paradox 6: Suppose that the population stock(prenominal) divagation (?) for a normally distri anded standardized stress of consummation is know to be 7.20. What would the standard error of the sample besotted ([pic]) be if we were to draw a random sample of 16 test scores? firmness: For this problem, since the population standard release is given, we utilise the polity on varlet 193. [pic] =[pic] Therefore: [pic] = [pic] =[pic] = 1.8 bother 7: Suppose that the random sample from difficulty 6 yielded these ascertained scores: 656125101113 121092023202818 a. Find the 95% boldness legal separation for the conceive. b. Find the 99% arrogance musical separation for the mean. Answer: The premier(prenominal) thing we need to do is meet the mean for these info (we will employ the population standard deviation but if we did not know it we would have to calculate that and use the t distribution). Using Excel the mean i s 13 (you should insist this tax for practice). a. directly the 95% confidence interval is raise apply the formula on page 196: 95% confidence interval = [pic] ± 1.96 [pic] so we then have: 13 ±1.96 (1.8) = 13 ± 3.528 = 9.47 to 16.53 b. Now the 99% confidence interval is open using the formula on page 197: 99% confidence interval = [pic] ± 2.58 [pic] so we then have: 13 ±2.58 (1.8) = 13 ± 4.644 = 8.36 to 17.

64 task 8 Now suppose that we do not flavour wanton assuming that ? = 7.20. Use the scores in Problem 7 to: a. estimate the standard error of the sample mean ([pic]). b. mystify the 95% confidence interval for the mean. c. insure the 99% confi dence interval for the mean. Answer: F! irst we need to find the standard deviation from our sample. I used Excel and found it to be (S = 6.899) but please verify! Now we would get the precedent Error of the mean using the formula on page 202: [pic] =[pic] a. Therefore: [pic] = [pic] =[pic] = 1.78 The general formula for the confidence interval is shown on page 205: Confidence...If you want to get a large essay, direct it on our website: OrderEssay.net

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